Score Plus

Hello, I am Jeab Hin frm Maeklong, near Bangkok in Thailand. This is a gr8 forum... please help me with this problem



Column A

A box contains 32 short pencils and 12 long pencils. The probability of picking 2 pencils, the first of which is short and the second one is long.

Column B

30%

jeab wrote:
Hello, I am Jeab Hin frm Maeklong, near Bangkok in Thailand. This is a gr8 forum... please help me with this problem



Column A

A box contains 32 short pencils and 12 long pencils. The probability of picking 2 pencils, the first of which is short and the second one is long.

Column B

30%

hi jeab...welcome to the forum..

let us evaluate column A..

probability of first picking short pencil is 32/44

probability of picking a long pencil then is 12/43

combined probability is 32/44 *12/43 ...approxinations tells us that ans is close to 20 %..

Hence, quantity in column B is greater than quantity in column A.

happy solving..

Hello, I am Jeab Hin frm Maeklong, near Bangkok in Thailand. This is a gr8 forum... please help me with this problem



Column A

A box contains 32 short pencils and 12 long pencils. The probability of picking 2 pencils, the first of which is short and the second one is long.

Column B

30%
Pranshu Here:
Following is the probable solution:
Column A(picking 2 pencils, the first of which is short and the second one is long.)=P(short pencil)*P(long pencil) = (32/44)*(12/43)=0.20=20%
Column B : 30%
Colum B is larger ie Answer is B.