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(A0 10!

(A) 10!

An editor is deciding on the composition of an upcoming edition of a historical journal. First, she must decide whether to include an optional editorial; next, she must choose 4 out of the total number of submitted articles; finally, she must choose 2 out of the total number of submitted book reviews. The editorial, when included, always comes first, and the 2 book reviews always come last. If a total of 5 book reviews were submitted, and the editor has a total of 67,200 possible ways to lay out the journal, what is the total number of articles that were submitted?

6
8
9
16
18



In putting together a last-minute vacation package, a traveler must choose a departing flight, a hotel, a rental car, and a return flight. The number of departing flights is 1 greater than the number of hotels, the number of hotels is 2 more than the number of rental cars, and there are as many return flights as departing flights. If 1 more departing flight was available, there would be 1176 total possibilities from which to choose. How many departing flights are there?


5
6
7
8
9


Janice has divided her department of 12 employees into 4 teams of 3 employees each to work on a new project. Four new employees are to be added to Janice’s department, but the number of teams is to remain the same. If every employee must be on exactly 1 team, then the total number of different teams into which Janice can divide the enlarged department is approximately how many times the number of different teams into which Janice could have divided the original department?

16
170
340
1820
43680

Hello Apoorva,

I have copied your questions here, please dont mind

P.S : Evrybody please try to avoid creating new threads for individual questions on topics for which there is an existing thread !!

Here is the question from Apoorva,

Meg and Bob are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?

A) 24
B ) 30
C) 60
D) 90
E) 120

Vijay wrote:
Answer is C

Bob position is 5 : Then other 4 p_layer_s can be 4*3*2*1 ways = 24
Bob position is 4 : Then meg has to be in 3,2,1 position so 3 ways and other 3 p_layer_s can be 3*2*1 ways , so 3*3*2*1 =18
Bob position is 3 : Then meg has to be in 2,1 position so 2 ways and other 3 p_layer_s can be 3*2*1 ways , so 2*3*2*1 =12
Bob position is 2 : Then meg has to be in 1 position so 1 way and other 3 p_layer_s can be 3*2*1 ways , so 1*3*2*1 = 6

Adding all possibilities we get 24 +18+12+6 = 60

Perfect answer and explanation Vijay !!

For a very interesting approach Check here :
http://score-plus.com/forum/gmat-problem-solving/permutations-and-combinations/view-3.html

Also check :
http://score-plus.com/forum/gmat-problem-solving/permutations-and-combinations/view-7.html

Cheers !!